Question #238326

Question 2

A flat belt is required to transmit 22 kW from a 250 mm diameter pulley running at 1450

rpm to a 355 mm diameter pulley. The proposed belt is 3.5 mm thick.

The other system specifications are as follows:

ï‚· Coefficient of friction 0.7,

ï‚· Density of the belt is 1100 kg/m3

ï‚· Maximum permissible stress is 7 MPa.

ï‚· The distance between the shafts is 1.8 m.

2.1 Calculate the width required. [15]

A flat belt is required to transmit 22 kW from a 250 mm diameter pulley running at 1450

rpm to a 355 mm diameter pulley. The proposed belt is 3.5 mm thick.

The other system specifications are as follows:

ï‚· Coefficient of friction 0.7,

ï‚· Density of the belt is 1100 kg/m3

ï‚· Maximum permissible stress is 7 MPa.

ï‚· The distance between the shafts is 1.8 m.

2.1 Calculate the width required. [15]

Expert's answer

Maximum tension T,

P = \frac{2\pi N T}{1000}

T =\frac{22000\times1000}{2\pi\times1450} = 2414.76 N

Width of belt b,

b = \frac{T}{\sigma\times t}= \frac{2414.76}{7\times 3.5}=98.56 mmÂ

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